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Exercises and Answers about Chemical Equilibrium in Gaseous System (Beberapa soal latihan beserta jawaban mengenai Keseimbangan Kimia dalam sistem Gas)


Exercises and Answers about Chemical Equilibrium in Gaseous System (Beberapa soal latihan beserta jawaban mengenai Keseimbangan Kimia dalam sistem Gas)

φ Write equilibrium expressions for Kp and Kc for each of the following reactions:

New Doc 2017-12-26_1

Jawaban : New Doc 2017-12-26_2

 

φ At 25 °C, the equilibrium constant Kc = 1,4 x 107  for the reaction:

New Doc 2017-12-26_3

    What is the value of Kc at this temperature for the following reactions:

New Doc 2017-12-26_3(2)

New Doc 2017-12-26_3(3)

Jawaban : New Doc 2017-12-26 (1)_1

φ Consider the following equilibria and their equilibrium constants:New Doc 2017-12-26_1(2)

Determine the equilibrium constant Kc for the reaction:

New Doc 2017-12-26_1(3)

Jawaban :

New Doc 2017-12-26_1(4)

φ  Arrange the following reactions in order of their increasing tendency to proceed toward completion:

New Doc 2017-12-26_1

Jawaban : Jika nilai “K” besar semakin tidak larut. Jadi, urutannya yaitu a → d → c → b

 

φ The following thermodynamic data apply at 25 °C :

Substance GoF (KJ / mol)
NiSO4.6H2O(s) -2222
NiSO4 (s) -773,6
H2O (g) -228

a. What is ∆ Go (in KJ) for the reaction: New Doc 2017-12-26_1(2)

b. What is Kp for this reaction?

Jawaban : 

a. ∆ Go = ∆ GoF NiSO+ ∆ GoF 6H2O – ∆ GoF NiSO4.6H2O

∆ Go = [ -773,6 + 6 (-228) – (-2222)]

∆ Go = 80,4 KJ

 

b. ∆ G = – RT ln Kp

80,4 KJ/mol = – 8,314 J/K mol (25 +273) K ln Kp

Kp = [H2O]6

80400 J/mol = – 8,314 J/ K mol (298) K ln Kp

80400 = – 2477,572 ln Kp

ln Kp = – 32,451

Kp = 8,06 x 10-15

 

φ The reaction :

New Doc 2017-12-26_1(3)

is also a source of Hydrogen. At 1500 °C, its value of Kc = 5,67. What is its value of Kp at this temperature?

Jawaban : New Doc 2017-12-26_1(8)

φ At 700 K, ∆ Go 700K = – 13,5 KJ for the reaction :New Doc 2017-12-26_1(4)

Calculate the value of Kp for the reaction at 700 K.

Jawaban :

New Doc 2017-12-26_2

φ The equilibrium constant, Kp, for the reaction :

New Doc 2017-12-26_1(5).jpg

has a value of 4,56 x 10-2 atm at 395 °C. What the value of ∆ Go 668K (in KJ) for this reaction?

Jawaban : New Doc 2017-12-26 (1)_2

φ Consider the equilibrium :New Doc 2017-12-26_1(6)

How would the following affect the position of equilibrium?

a. addition of PCl→ reaksi bergeser ke kanan

b. removal of Cl2 reaksi bergeser ke kiri

c. removal of PCl5reaksi bergeser ke kanan

d. decrease in the volume of container tidak ada perubahan

e. addition of He without a change in volume tidak ada perubahan

Nb : Jawaban yang berwarna hijau

 

φ Indicate how each of the following changes affect the amount of H in the system below, for which ∆Hreaction = +41 KJ (Endoterm).

New Doc 2017-12-26_1(7)

a. addition of CO2 → reaksi bergeser ke kanan

b. addition of H2Oreaksi bergeser ke kiri

c. addition of Catalysttidak ada perubahan (reaksinya cepat)

d. increase in temperature reaksi bergeser ke kiri

e. decrease in the volume of the container tidak ada perubahan

Nb : Jawaban yang berwarna hijau

 

φ In a particular experiment the following partial pressures were determined for the reaction at equilibrium :

New Doc 2017-12-26_1

p NO = 0,65 atm,   p Cl2 = 0,18 atm,   p NOCl = 0,15 atm

What is Kp for this reaction at the temperature at which the experiment was performed?

Jawaban :

New Doc 2017-12-26_1(2)

 

φ At 25 °C, 0,0560 mol of O2 and 0.020 mol N2O were placed in a 1,00 L vessel and allowed to react according to the equation:

New Doc 2017-12-26_1

When the system reached equilibrium, the concentration of the NO2 was found to be 0,020 mol/L.

a. what were the equilibrium molar concentration of N2O and O2 ?

b. what is the value of Kc for this reaction at 25 °C ?

Jawaban :

New Doc 2017-12-26_2

φ For the reaction :

New Doc 2017-12-26_1

Kc = 0,771 at 750 °C. If 1,00 mol of H2 and 1,00 mol of CO2 are placed into a 5,00 L container and permitted to react, what will the concentrations of all four gases be at equilibrium?

Jawaban :

New Doc 2017-12-26_2

New Doc 2017-12-26 (1)_1

 

 


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